Sone 363 is equivalent to approximately 125 decibels.
Taking the log base 2 of both sides: [ \log_2(363) \approx 8.5 ] [ \fracx - 4010 = 8.5 ] [ x = 125 \text dB SPL ] sone 363
[ \textSones = 2^\left( \frac\textdB - 4010 \right) ] Sone 363 is equivalent to approximately 125 decibels
Let us solve for decibels at 363 sones: